15x^2-7-5x(3x/4)=3(7-4x)

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Solution for 15x^2-7-5x(3x/4)=3(7-4x) equation: 



15x^2-7-5x(3x/4)=3(7-4x)

We move all terms to the left:

15x^2-7-5x(3x/4)-(3(7-4x))=0

We add all the numbers together, and all the variables

15x^2-5x(+3x/4)-(3(-4x+7))-7=0

We multiply parentheses

15x^2-15x^2-(3(-4x+7))-7=0



We calculate terms in parentheses: -(3(-4x+7)), so:

3(-4x+7)

We multiply parentheses

-12x+21

Back to the equation:

-(-12x+21)



We add all the numbers together, and all the variables

-(-12x+21)-7=0

We get rid of parentheses

12x-21-7=0

We add all the numbers together, and all the variables

12x-28=0

We move all terms containing x to the left, all other terms to the right

12x=28

x=28/12

x=2+1/3

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